3(10x^2-29x+10)=0

Solution for 3(10x^2-29x+10)=0 equation:

3(10x^2-29x+10)=0

We multiply parentheses

30x^2-87x+30=0

a = 30; b = -87; c = +30;
Δ = b2-4ac
Δ = -872-4·30·30
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-87)-63}{2*30}=\frac{24}{60}
=2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-87)+63}{2*30}=\frac{150}{60}
=2+1/2
$